In this post, we can provide 50 multiple-choice JavaScript questions and answers, with the help of this you can prepare your javascript interview easily.
If you like this post so we can provide the next 50 + 50 questions and answers in the next part.
150 JavaScript Questions Part 1
101. What's the value of output?
const one = false || {} || null;
const two = null || false || '';
const three = [] || 0 || true;
console.log(one, two, three);
- A:
false
null
[]
- B:
null
""
true
- C:
{}
""
[]
- D:
null
null
true
Answer
#### Answer: C
With the ||
operator, we can return the first truthy operand. If all values are falsy, the last operand gets returned.
(false || {} || null)
: the empty object {}
is a truthy value. This is the first (and only) truthy value, which gets returned. one
is equal to {}
.
(null || false || "")
: all operands are falsy values. This means that the last operand, ""
gets returned. two
is equal to ""
.
([] || 0 || "")
: the empty array[]
is a truthy value. This is the first truthy value, which gets returned. three
is equal to []
.
102. What's the value of output?
const myPromise = () => Promise.resolve('I have resolved!');
function firstFunction() {
myPromise().then(res => console.log(res));
console.log('second');
}
async function secondFunction() {
console.log(await myPromise());
console.log('second');
}
firstFunction();
secondFunction();
- A:
I have resolved!
,second
andI have resolved!
,second
- B:
second
,I have resolved!
andsecond
,I have resolved!
- C:
I have resolved!
,second
andsecond
,I have resolved!
- D:
second
,I have resolved!
andI have resolved!
,second
Answer
#### Answer: D
With a promise, we basically say I want to execute this function, but I'll put it aside for now while it's running since this might take a while. Only when a certain value is resolved (or rejected), and when the call stack is empty, I want to use this value.
We can get this value with both .then
and the await
keyword in an async
function. Although we can get a promise's value with both .then
and await
, they work a bit differently.
In the firstFunction
, we (sort of) put the myPromise function aside while it was running, but continued running the other code, which is console.log('second')
in this case. Then, the function resolved with the string I have resolved
, which then got logged after it saw that the callstack was empty.
With the await keyword in secondFunction
, we literally pause the execution of an async function until the value has been resolved before moving to the next line.
This means that it waited for the myPromise
to resolve with the value I have resolved
, and only once that happened, we moved to the next line: second
got logged.
103. What's the value of output?
const set = new Set();
set.add(1);
set.add('Lydia');
set.add({ name: 'Lydia' });
for (let item of set) {
console.log(item + 2);
}
- A:
3
,NaN
,NaN
- B:
3
,7
,NaN
- C:
3
,Lydia2
,[object Object]2
- D:
"12"
,Lydia2
,[object Object]2
Answer
#### Answer: C
The +
operator is not only used for adding numerical values, but we can also use it to concatenate strings. Whenever the JavaScript engine sees that one or more values are not a number, it coerces the number into a string.
The first one is 1
, which is a numerical value. 1 + 2
returns the number 3.
However, the second one is a string "Lydia"
. "Lydia"
is a string and 2
is a number: 2
gets coerced into a string. "Lydia"
and "2"
get concatenated, which results in the string "Lydia2"
.
{ name: "Lydia" }
is an object. Neither a number nor an object is a string, so it stringifies both. Whenever we stringify a regular object, it becomes "[object Object]"
. "[object Object]"
concatenated with "2"
becomes "[object Object]2"
.
104. What's its value?
Promise.resolve(5);
- A:
5
- B:
Promise {<pending>: 5}
- C:
Promise {<fulfilled>: 5}
- D:
Error
Answer
#### Answer: C
We can pass any type of value we want to Promise.resolve
, either a promise or a non-promise. The method itself returns a promise with the resolved value (<fulfilled>
). If you pass a regular function, it'll be a resolved promise with a regular value. If you pass a promise, it'll be a resolved promise with the resolved value of that passed promise.
In this case, we just passed the numerical value 5
. It returns a resolved promise with the value 5
.
105. What's its value?
function compareMembers(person1, person2 = person) {
if (person1 !== person2) {
console.log('Not the same!');
} else {
console.log('They are the same!');
}
}
const person = { name: 'Lydia' };
compareMembers(person);
- A:
Not the same!
- B:
They are the same!
- C:
ReferenceError
- D:
SyntaxError
Answer
#### Answer: B
Objects are passed by reference. When we check objects for strict equality (===
), we're comparing their references.
We set the default value for person2
equal to the person
object, and passed the person
object as the value for person1
.
This means that both values have a reference to the same spot in memory, thus they are equal.
The code block in the else
statement gets run, and They are the same!
gets logged.
106. What's its value?
const colorConfig = {
red: true,
blue: false,
green: true,
black: true,
yellow: false,
};
const colors = ['pink', 'red', 'blue'];
console.log(colorConfig.colors[1]);
- A:
true
- B:
false
- C:
undefined
- D:
TypeError
Answer
#### Answer: D
In JavaScript, we have two ways to access properties on an object: bracket notation, or dot notation. In this example, we use dot notation (colorConfig.colors
) instead of bracket notation (colorConfig["colors"]
).
With dot notation, JavaScript tries to find the property on the object with that exact name. In this example, JavaScript tries to find a property called colors
on the colorConfig
object. There is no property called colors
, so this returns undefined
. Then, we try to access the value of the first element by using [1]
. We cannot do this on a value that's undefined
, so it throws a TypeError
: Cannot read property '1' of undefined
.
JavaScript interprets (or unboxes) statements. When we use bracket notation, it sees the first opening bracket [
and keeps going until it finds the closing bracket ]
. Only then, it will evaluate the statement. If we would've used colorConfig[colors[1]]
, it would have returned the value of the red
property on the colorConfig
object.
107. What's its value?
console.log('❤️' === '❤️');
- A:
true
- B:
false
Answer
#### Answer: A
Under the hood, emojis are unicodes. The unicodes for the heart emoji is "U+2764 U+FE0F"
. These are always the same for the same emojis, so we're comparing two equal strings to each other, which returns true.
108. Which of these methods modifies the original array?
const emojis = ['✨', '🥑', '😍'];
emojis.map(x => x + '✨');
emojis.filter(x => x !== '🥑');
emojis.find(x => x !== '🥑');
emojis.reduce((acc, cur) => acc + '✨');
emojis.slice(1, 2, '✨');
emojis.splice(1, 2, '✨');
- A:
All of them
- B:
map
reduce
slice
splice
- C:
map
slice
splice
- D:
splice
Answer
#### Answer: D
With splice
method, we modify the original array by deleting, replacing or adding elements. In this case, we removed 2 items from index 1 (we removed '🥑'
and '😍'
) and added the ✨ emoji instead.
map
, filter
and slice
return a new array, find
returns an element, and reduce
returns a reduced value.
109. What's the output?
const food = ['🍕', '🍫', '🥑', '🍔'];
const info = { favoriteFood: food[0] };
info.favoriteFood = '🍝';
console.log(food);
- A:
['🍕', '🍫', '🥑', '🍔']
- B:
['🍝', '🍫', '🥑', '🍔']
- C:
['🍝', '🍕', '🍫', '🥑', '🍔']
- D:
ReferenceError
Answer
#### Answer: A
We set the value of the favoriteFood
property on the info
object equal to the string with the pizza emoji, '🍕'
. A string is a primitive data type. In JavaScript, primitive data types don't interact by reference.
In JavaScript, primitive data types (everything that's not an object) interact by value. In this case, we set the value of the favoriteFood
property on the info
object equal to the value of the first element in the food
array, the string with the pizza emoji in this case ('🍕'
). A string is a primitive data type, and interact by value (see my blogpost if you're interested in learning more)
Then, we change the value of the favoriteFood
property on the info
object. The food
array hasn't changed, since the value of favoriteFood
was merely a copy of the value of the first element in the array, and doesn't have a reference to the same spot in memory as the element on food[0]
. When we log food, it's still the original array, ['🍕', '🍫', '🥑', '🍔']
.
110. What does this method do?
JSON.parse();
- A: Parses JSON to a JavaScript value
- B: Parses a JavaScript object to JSON
- C: Parses any JavaScript value to JSON
- D: Parses JSON to a JavaScript object only
Answer
#### Answer: A
With the JSON.parse()
method, we can parse JSON string to a JavaScript value.
javascript
// Stringifying a number into valid JSON, then parsing the JSON string to a JavaScript value:
const jsonNumber = JSON.stringify(4); // '4'
JSON.parse(jsonNumber); // 4
// Stringifying an array value into valid JSON, then parsing the JSON string to a JavaScript value:
const jsonArray = JSON.stringify([1, 2, 3]); // '[1, 2, 3]'
JSON.parse(jsonArray); // [1, 2, 3]
// Stringifying an object into valid JSON, then parsing the JSON string to a JavaScript value:
const jsonArray = JSON.stringify({ name: 'Lydia' }); // '{"name":"Lydia"}'
JSON.parse(jsonArray); // { name: 'Lydia' }
111. What's the output?
let name = 'Lydia';
function getName() {
console.log(name);
let name = 'Sarah';
}
getName();
- A: Lydia
- B: Sarah
- C:
undefined
- D:
ReferenceError
Answer
#### Answer: D
Each function has its own execution context (or scope). The getName
function first looks within its own context (scope) to see if it contains the variable name
we're trying to access. In this case, the getName
function contains its own name
variable: we declare the variable name
with the let
keyword, and with the value of 'Sarah'
.
Variables with the let
keyword (and const
) are hoisted, but unlike var
, don't get initialized. They are not accessible before the line we declare (initialize) them. This is called the "temporal dead zone". When we try to access the variables before they are declared, JavaScript throws a ReferenceError
.
If we wouldn't have declared the name
variable within the getName
function, the javascript engine would've looked down the scope chain. The outer scope has a variable called name
with the value of Lydia
. In that case, it would've logged Lydia
.
javascript
let name = 'Lydia';
function getName() {
console.log(name);
}
getName(); // Lydia
112. What's the output?
function* generatorOne() {
yield ['a', 'b', 'c'];
}
function* generatorTwo() {
yield* ['a', 'b', 'c'];
}
const one = generatorOne();
const two = generatorTwo();
console.log(one.next().value);
console.log(two.next().value);
- A:
a
anda
- B:
a
andundefined
- C:
['a', 'b', 'c']
anda
- D:
a
and['a', 'b', 'c']
Answer
#### Answer: C
With the yield
keyword, we yield
values in a generator function. With the yield*
keyword, we can yield values from another generator function, or iterable object (for example an array).
In generatorOne
, we yield the entire array ['a', 'b', 'c']
using the yield
keyword. The value of value
property on the object returned by the next
method on one
(one.next().value
) is equal to the entire array ['a', 'b', 'c']
.
javascript
console.log(one.next().value); // ['a', 'b', 'c']
console.log(one.next().value); // undefined
In generatorTwo
, we use the yield*
keyword. This means that the first yielded value of two
, is equal to the first yielded value in the iterator. The iterator is the array ['a', 'b', 'c']
. The first yielded value is a
, so the first time we call two.next().value
, a
is returned.
javascript
console.log(two.next().value); // 'a'
console.log(two.next().value); // 'b'
console.log(two.next().value); // 'c'
console.log(two.next().value); // undefined
113. What's the output?
console.log(`${(x => x)('I love')} to program`);
- A:
I love to program
- B:
undefined to program
- C:
${(x => x)('I love') to program
- D:
TypeError
Answer
#### Answer: A
Expressions within template literals are evaluated first. This means that the string will contain the returned value of the expression, the immediately invoked function (x => x)('I love')
in this case. We pass the value 'I love'
as an argument to the x => x
arrow function. x
is equal to 'I love'
, which gets returned. This results in I love to program
.
114. What will happen?
let config = {
alert: setInterval(() => {
console.log('Alert!');
}, 1000),
};
config = null;
- A: The
setInterval
callback won't be invoked - B: The
setInterval
callback gets invoked once - C: The
setInterval
callback will still be called every second - D: We never invoked
config.alert()
, config isnull
Answer
#### Answer: C
Normally when we set objects equal to null
, those objects get garbage collected as there is no reference anymore to that object. However, since the callback function within setInterval
is an arrow function (thus bound to the config
object), the callback function still holds a reference to the config
object.
As long as there is a reference, the object won't get garbage collected.
Since this is an interval, setting config
to null
or delete
-ing config.alert
won't garbage-collect the interval, so the interval will still be called.
It should be cleared with clearInterval(config.alert)
to remove it from memory.
Since it was not cleared, the setInterval
callback function will still get invoked every 1000ms (1s).
115. Which method(s) will return the value 'Hello world!'
?
const myMap = new Map();
const myFunc = () => 'greeting';
myMap.set(myFunc, 'Hello world!');
//1
myMap.get('greeting');
//2
myMap.get(myFunc);
//3
myMap.get(() => 'greeting');
- A: 1
- B: 2
- C: 2 and 3
- D: All of them
Answer
#### Answer: B
When adding a key/value pair using the set
method, the key will be the value of the first argument passed to the set
function, and the value will be the second argument passed to the set
function. The key is the function () => 'greeting'
in this case, and the value 'Hello world'
. myMap
is now { () => 'greeting' => 'Hello world!' }
.
1 is wrong, since the key is not 'greeting'
but () => 'greeting'
.
3 is wrong, since we're creating a new function by passing it as a parameter to the get
method. Object interact by reference. Functions are objects, which is why two functions are never strictly equal, even if they are identical: they have a reference to a different spot in memory.
116. What's the output?
const person = {
name: 'Lydia',
age: 21,
};
const changeAge = (x = { ...person }) => (x.age += 1);
const changeAgeAndName = (x = { ...person }) => {
x.age += 1;
x.name = 'Sarah';
};
changeAge(person);
changeAgeAndName();
console.log(person);
- A:
{name: "Sarah", age: 22}
- B:
{name: "Sarah", age: 23}
- C:
{name: "Lydia", age: 22}
- D:
{name: "Lydia", age: 23}
Answer
#### Answer: C
Both the changeAge
and changeAgeAndName
functions have a default parameter, namely a newly created object { ...person }
. This object has copies of all the key/values in the person
object.
First, we invoke the changeAge
function and pass the person
object as its argument. This function increases the value of the age
property by 1. person
is now { name: "Lydia", age: 22 }
.
Then, we invoke the changeAgeAndName
function, however we don't pass a parameter. Instead, the value of x
is equal to a new object: { ...person }
. Since it's a new object, it doesn't affect the values of the properties on the person
object. person
is still equal to { name: "Lydia", age: 22 }
.
117. Which of the following options will return 6
?
function sumValues(x, y, z) {
return x + y + z;
}
- A:
sumValues([...1, 2, 3])
- B:
sumValues([...[1, 2, 3]])
- C:
sumValues(...[1, 2, 3])
- D:
sumValues([1, 2, 3])
Answer
#### Answer: C
With the spread operator ...
, we can spread iterables to individual elements. The sumValues
function receives three arguments: x
, y
and z
. ...[1, 2, 3]
will result in 1, 2, 3
, which we pass to the sumValues
function.
118. What's the output?
let num = 1;
const list = ['🥳', '🤠', '🥰', '🤪'];
console.log(list[(num += 1)]);
- A:
🤠
- B:
🥰
- C:
SyntaxError
- D:
ReferenceError
Answer
#### Answer: B
With the +=
operand, we're incrementing the value of num
by 1
. num
had the initial value 1
, so 1 + 1
is 2
. The item on the second index in the list
array is 🥰, console.log(list[2])
prints 🥰.
119. What's the output?
const person = {
firstName: 'Lydia',
lastName: 'Hallie',
pet: {
name: 'Mara',
breed: 'Dutch Tulip Hound',
},
getFullName() {
return `${this.firstName} ${this.lastName}`;
},
};
console.log(person.pet?.name);
console.log(person.pet?.family?.name);
console.log(person.getFullName?.());
console.log(member.getLastName?.());
- A:
undefined
undefined
undefined
undefined
- B:
Mara
undefined
Lydia Hallie
ReferenceError
- C:
Mara
null
Lydia Hallie
null
- D:
null
ReferenceError
null
ReferenceError
Answer
#### Answer: B
With the optional chaining operator ?.
, we no longer have to explicitly check whether the deeper nested values are valid or not. If we're trying to access a property on an undefined
or null
value (nullish), the expression short-circuits and returns undefined
.
person.pet?.name
: person
has a property named pet
: person.pet
is not nullish. It has a property called name
, and returns Mara
.
person.pet?.family?.name
: person
has a property named pet
: person.pet
is not nullish. pet
does not have a property called family
, person.pet.family
is nullish. The expression returns undefined
.
person.getFullName?.()
: person
has a property named getFullName
: person.getFullName()
is not nullish and can get invoked, which returns Lydia Hallie
.
member.getLastName?.()
: member
is not defined: member.getLastName()
is nullish. The expression returns undefined
.
120. What's the output?
const groceries = ['banana', 'apple', 'peanuts'];
if (groceries.indexOf('banana')) {
console.log('We have to buy bananas!');
} else {
console.log(`We don't have to buy bananas!`);
}
- A: We have to buy bananas!
- B: We don't have to buy bananas
- C:
undefined
- D:
1
Answer
#### Answer: B
We passed the condition groceries.indexOf("banana")
to the if-statement. groceries.indexOf("banana")
returns 0
, which is a falsy value. Since the condition in the if-statement is falsy, the code in the else
block runs, and We don't have to buy bananas!
gets logged.
121. What's the output?
const config = {
languages: [],
set language(lang) {
return this.languages.push(lang);
},
};
console.log(config.language);
- A:
function language(lang) { this.languages.push(lang }
- B:
0
- C:
[]
- D:
undefined
Answer
#### Answer: D
The language
method is a setter
. Setters don't hold an actual value, their purpose is to modify properties. When calling a setter
method, undefined
gets returned.
122. What's the output?
const name = 'Lydia Hallie';
console.log(!typeof name === 'object');
console.log(!typeof name === 'string');
- A:
false
true
- B:
true
false
- C:
false
false
- D:
true
true
Answer
#### Answer: C
typeof name
returns "string"
. The string "string"
is a truthy value, so !typeof name
returns the boolean value false
. false === "object"
and false === "string"
both returnfalse
.
(If we wanted to check whether the type was (un)equal to a certain type, we should've written !==
instead of !typeof
)
123. What's the output?
const add = x => y => z => {
console.log(x, y, z);
return x + y + z;
};
add(4)(5)(6);
- A:
4
5
6
- B:
6
5
4
- C:
4
function
function
- D:
undefined
undefined
6
Answer
#### Answer: A
The add
function returns an arrow function, which returns an arrow function, which returns an arrow function (still with me?). The first function receives an argument x
with the value of 4
. We invoke the second function, which receives an argument y
with the value 5
. Then we invoke the third function, which receives an argument z
with the value 6
. When we're trying to access the value x
, y
and z
within the last arrow function, the JS engine goes up the scope chain in order to find the values for x
and y
accordingly. This returns 4
5
6
.
124. What's the output?
async function* range(start, end) {
for (let i = start; i <= end; i++) {
yield Promise.resolve(i);
}
}
(async () => {
const gen = range(1, 3);
for await (const item of gen) {
console.log(item);
}
})();
- A:
Promise {1}
Promise {2}
Promise {3}
- B:
Promise {<pending>}
Promise {<pending>}
Promise {<pending>}
- C:
1
2
3
- D:
undefined
undefined
undefined
Answer
#### Answer: C
The generator function range
returns an async object with promises for each item in the range we pass: Promise{1}
, Promise{2}
, Promise{3}
. We set the variable gen
equal to the async object, after which we loop over it using a for await ... of
loop. We set the variable item
equal to the returned Promise values: first Promise{1}
, then Promise{2}
, then Promise{3}
. Since we're awaiting the value of item
, the resolved promsie, the resolved values of the promises get returned: 1
, 2
, then 3
.
125. What's the output?
const myFunc = ({ x, y, z }) => {
console.log(x, y, z);
};
myFunc(1, 2, 3);
- A:
1
2
3
- B:
{1: 1}
{2: 2}
{3: 3}
- C:
{ 1: undefined }
undefined
undefined
- D:
undefined
undefined
undefined
Answer
#### Answer: D
myFunc
expects an object with properties x
, y
and z
as its argument. Since we're only passing three separate numeric values (1, 2, 3) instead of one object with properties x
, y
and z
({x: 1, y: 2, z: 3}), x
, y
and z
have their default value of undefined
.
126. What's the output?
function getFine(speed, amount) {
const formattedSpeed = new Intl.NumberFormat('en-US', {
style: 'unit',
unit: 'mile-per-hour'
}).format(speed);
const formattedAmount = new Intl.NumberFormat('en-US', {
style: 'currency',
currency: 'USD'
}).format(amount);
return `The driver drove ${formattedSpeed} and has to pay ${formattedAmount}`;
}
console.log(getFine(130, 300))
- A: The driver drove 130 and has to pay 300
- B: The driver drove 130 mph and has to pay \$300.00
- C: The driver drove undefined and has to pay undefined
- D: The driver drove 130.00 and has to pay 300.00
Answer
#### Answer: B
With the Intl.NumberFormat
method, we can format numeric values to any locale. We format the numeric value 130
to the en-US
locale as a unit
in mile-per-hour
, which results in 130 mph
. The numeric value 300
to the en-US
locale as a currency
in USD
results in $300.00
.
127. What's the output?
const spookyItems = ['👻', '🎃', '🕸'];
({ item: spookyItems[3] } = { item: '💀' });
console.log(spookyItems);
- A:
["👻", "🎃", "🕸"]
- B:
["👻", "🎃", "🕸", "💀"]
- C:
["👻", "🎃", "🕸", { item: "💀" }]
- D:
["👻", "🎃", "🕸", "[object Object]"]
Answer
#### Answer: B
By destructuring objects, we can unpack values from the right-hand object, and assign the unpacked value to the value of the same property name on the left-hand object. In this case, we're assigning the value "💀" to spookyItems[3]
. This means that we're modifying the spookyItems
array, we're adding the "💀" to it. When logging spookyItems
, ["👻", "🎃", "🕸", "💀"]
gets logged.
128. What's the output?
const name = 'Lydia Hallie';
const age = 21;
console.log(Number.isNaN(name));
console.log(Number.isNaN(age));
console.log(isNaN(name));
console.log(isNaN(age));
- A:
true
false
true
false
- B:
true
false
false
false
- C:
false
false
true
false
- D:
false
true
false
true
Answer
#### Answer: C
With the Number.isNaN
method, you can check if the value you pass is a numeric value and equal to NaN
. name
is not a numeric value, so Number.isNaN(name)
returns false
. age
is a numeric value, but is not equal to NaN
, so Number.isNaN(age)
returns false
.
With the isNaN
method, you can check if the value you pass is not a number. name
is not a number, so isNaN(name)
returns true. age
is a number, so isNaN(age)
returns false
.
129. What's the output?
const randomValue = 21;
function getInfo() {
console.log(typeof randomValue);
const randomValue = 'Lydia Hallie';
}
getInfo();
- A:
"number"
- B:
"string"
- C:
undefined
- D:
ReferenceError
Answer
#### Answer: D
Variables declared with the const
keyword are not referencable before their initialization: this is called the temporal dead zone. In the getInfo
function, the variable randomValue
is scoped in the functional scope of getInfo
. On the line where we want to log the value of typeof randomValue
, the variable randomValue
isn't initialized yet: a ReferenceError
gets thrown! The engine didn't go down the scope chain since we declared the variable randomValue
in the getInfo
function.
130. What's the output?
const myPromise = Promise.resolve('Woah some cool data');
(async () => {
try {
console.log(await myPromise);
} catch {
throw new Error(`Oops didn't work`);
} finally {
console.log('Oh finally!');
}
})();
- A:
Woah some cool data
- B:
Oh finally!
- C:
Woah some cool data
Oh finally!
- D:
Oops didn't work
Oh finally!
Answer
#### Answer: C
In the try
block, we're logging the awaited value of the myPromise
variable: "Woah some cool data"
. Since no errors were thrown in the try
block, the code in the catch
block doesn't run. The code in the finally
block always runs, "Oh finally!"
gets logged.
131. What's the output?
const emojis = ['🥑', ['✨', '✨', ['🍕', '🍕']]];
console.log(emojis.flat(1));
- A:
['🥑', ['✨', '✨', ['🍕', '🍕']]]
- B:
['🥑', '✨', '✨', ['🍕', '🍕']]
- C:
['🥑', ['✨', '✨', '🍕', '🍕']]
- D:
['🥑', '✨', '✨', '🍕', '🍕']
Answer
#### Answer: B
With the flat
method, we can create a new, flattened array. The depth of the flattened array depends on the value that we pass. In this case, we passed the value 1
(which we didn't have to, that's the default value), meaning that only the arrays on the first depth will be concatenated. ['🥑']
and ['✨', '✨', ['🍕', '🍕']]
in this case. Concatenating these two arrays results in ['🥑', '✨', '✨', ['🍕', '🍕']]
.
132. What's the output?
class Counter {
constructor() {
this.count = 0;
}
increment() {
this.count++;
}
}
const counterOne = new Counter();
counterOne.increment();
counterOne.increment();
const counterTwo = counterOne;
counterTwo.increment();
console.log(counterOne.count);
- A:
0
- B:
1
- C:
2
- D:
3
Answer
#### Answer: D
counterOne
is an instance of the Counter
class. The counter class contains a count
property on its constructor, and an increment
method. First, we invoked the increment
method twice by calling counterOne.increment()
. Currently, counterOne.count
is 2
.
Then, we create a new variable counterTwo
, and set it equal to counterOne
. Since objects interact by reference, we're just creating a new reference to the same spot in memory that counterOne
points to. Since it has the same spot in memory, any changes made to the object that counterTwo
has a reference to, also apply to counterOne
. Currently, counterTwo.count
is 2
.
We invoke the counterTwo.increment()
, which sets the count
to 3
. Then, we log the count on counterOne
, which logs 3
.
133. What's the output?
const myPromise = Promise.resolve(Promise.resolve('Promise!'));
function funcOne() {
myPromise.then(res => res).then(res => console.log(res));
setTimeout(() => console.log('Timeout!'), 0);
console.log('Last line!');
}
async function funcTwo() {
const res = await myPromise;
console.log(await res);
setTimeout(() => console.log('Timeout!'), 0);
console.log('Last line!');
}
funcOne();
funcTwo();
- A:
Promise! Last line! Promise! Last line! Last line! Promise!
- B:
Last line! Timeout! Promise! Last line! Timeout! Promise!
- C:
Promise! Last line! Last line! Promise! Timeout! Timeout!
- D:
Last line! Promise! Promise! Last line! Timeout! Timeout!
Answer
#### Answer: D
First, we invoke funcOne
. On the first line of funcOne
, we call the myPromise
promise, which is an asynchronous operation. While the engine is busy completing the promise, it keeps on running the function funcOne
. The next line is the asynchronous setTimeout
function, from which the callback is sent to the Web API. (see my article on the event loop here.)
Both the promise and the timeout are asynchronous operations, the function keeps on running while it's busy completing the promise and handling the setTimeout
callback. This means that Last line!
gets logged first, since this is not an asynchonous operation. This is the last line of funcOne
, the promise resolved, and Promise!
gets logged. However, since we're invoking funcTwo()
, the call stack isn't empty, and the callback of the setTimeout
function cannot get added to the callstack yet.
In funcTwo
we're, first awaiting the myPromise promise. With the await
keyword, we pause the execution of the function until the promise has resolved (or rejected). Then, we log the awaited value of res
(since the promise itself returns a promise). This logs Promise!
.
The next line is the asynchronous setTimeout
function, from which the callback is sent to the Web API.
We get to the last line of funcTwo
, which logs Last line!
to the console. Now, since funcTwo
popped off the call stack, the call stack is empty. The callbacks waiting in the queue (() => console.log("Timeout!")
from funcOne
, and () => console.log("Timeout!")
from funcTwo
) get added to the call stack one by one. The first callback logs Timeout!
, and gets popped off the stack. Then, the second callback logs Timeout!
, and gets popped off the stack. This logs Last line! Promise! Promise! Last line! Timeout! Timeout!
134. How can we invoke sum
in sum.js
from index.js?
// sum.js
export default function sum(x) {
return x + x;
}
// index.js
import * as sum from './sum';
- A:
sum(4)
- B:
sum.sum(4)
- C:
sum.default(4)
- D: Default aren't imported with
*
, only named exports
Answer
#### Answer: C
With the asterisk *
, we import all exported values from that file, both default and named. If we had the following file:
javascript
// info.js
export const name = 'Lydia';
export const age = 21;
export default 'I love JavaScript';
// index.js
import * as info from './info';
console.log(info);
The following would get logged:
javascript
{
default: "I love JavaScript",
name: "Lydia",
age: 21
}
For the sum
example, it means that the imported value sum
looks like this:
javascript
{ default: function sum(x) { return x + x } }
We can invoke this function, by calling sum.default
135. What's the output?
const handler = {
set: () => console.log('Added a new property!'),
get: () => console.log('Accessed a property!'),
};
const person = new Proxy({}, handler);
person.name = 'Lydia';
person.name;
- A:
Added a new property!
- B:
Accessed a property!
- C:
Added a new property!
Accessed a property!
- D: Nothing gets logged
Answer
#### Answer: C
With a Proxy object, we can add custom behavior to an object that we pass to it as the second argument. In this case, we pass the handler
object which contained to properties: set
and get
. set
gets invoked whenever we set property values, get
gets invoked whenever we get (access) property values.
The first argument is an empty object {}
, which is the value of person
. To this object, the custom behavior specified in the handler
object gets added. If we add a property to the person
object, set
will get invoked. If we access a property on the person
object, get
gets invoked.
First, we added a new property name
to the proxy object (person.name = "Lydia"
). set
gets invoked, and logs "Added a new property!"
.
Then, we access a property value on the proxy object, the get
property on the handler object got invoked. "Accessed a property!"
gets logged.
136. Which of the following will modify the person
object?
const person = { name: 'Lydia Hallie' };
Object.seal(person);
- A:
person.name = "Evan Bacon"
- B:
person.age = 21
- C:
delete person.name
- D:
Object.assign(person, { age: 21 })
Answer
#### Answer: A
With Object.seal
we can prevent new properies from being added, or existing properties to be removed.
However, you can still modify the value of existing properties.
137. Which of the following will modify the person
object?
const person = {
name: 'Lydia Hallie',
address: {
street: '100 Main St',
},
};
Object.freeze(person);
- A:
person.name = "Evan Bacon"
- B:
delete person.address
- C:
person.address.street = "101 Main St"
- D:
person.pet = { name: "Mara" }
Answer
#### Answer: C
The Object.freeze
method freezes an object. No properties can be added, modified, or removed.
However, it only shallowly freezes the object, meaning that only direct properties on the object are frozen. If the property is another object, like address
in this case, the properties on that object aren't frozen, and can be modified.
138. What's the output?
const add = x => x + x;
function myFunc(num = 2, value = add(num)) {
console.log(num, value);
}
myFunc();
myFunc(3);
- A:
2
4
and3
6
- B:
2
NaN
and3
NaN
- C:
2
Error
and3
6
- D:
2
4
and3
Error
Answer
#### Answer: A
First, we invoked myFunc()
without passing any arguments. Since we didn't pass arguments, num
and value
got their default values: num is 2
, and value
the returned value of the function add
. To the add
function, we pass num
as an argument, which had the value of 2
. add
returns 4
, which is the value of value
.
Then, we invoked myFunc(3)
and passed the value 3
as the value for the argument num
. We didn't pass an argument for value
. Since we didn't pass a value for the value
argument, it got the default value: the returned value of the add
function. To add
, we pass num
, which has the value of 3
. add
returns 6
, which is the value of value
.
139. What's the output?
class Counter {
#number = 10
increment() {
this.#number++
}
getNum() {
return this.#number
}
}
const counter = new Counter()
counter.increment()
console.log(counter.#number)
- A:
10
- B:
11
- C:
undefined
- D:
SyntaxError
Answer
#### Answer: D
In ES2020, we can add private variables in classes by using the #
. We cannot access these variables outside of the class. When we try to log counter.#number
, a SyntaxError gets thrown: we cannot acccess it outside the Counter
class!
140. What's missing?
const teams = [
{ name: 'Team 1', members: ['Paul', 'Lisa'] },
{ name: 'Team 2', members: ['Laura', 'Tim'] },
];
function* getMembers(members) {
for (let i = 0; i < members.length; i++) {
yield members[i];
}
}
function* getTeams(teams) {
for (let i = 0; i < teams.length; i++) {
// ✨ SOMETHING IS MISSING HERE ✨
}
}
const obj = getTeams(teams);
obj.next(); // { value: "Paul", done: false }
obj.next(); // { value: "Lisa", done: false }
- A:
yield getMembers(teams[i].members)
- B:
yield* getMembers(teams[i].members)
- C:
return getMembers(teams[i].members)
- D:
return yield getMembers(teams[i].members)
Answer
#### Answer: B
In order to iterate over the members
in each element in the teams
array, we need to pass teams[i].members
to the getMembers
generator function. The generator function returns a generator object. In order to iterate over each element in this generator object, we need to use yield*
.
If we would've written yield
, return yield
, or return
, the entire generator function would've gotten returned the first time we called the next
method.
141. What's the output?
const person = {
name: 'Lydia Hallie',
hobbies: ['coding'],
};
function addHobby(hobby, hobbies = person.hobbies) {
hobbies.push(hobby);
return hobbies;
}
addHobby('running', []);
addHobby('dancing');
addHobby('baking', person.hobbies);
console.log(person.hobbies);
- A:
["coding"]
- B:
["coding", "dancing"]
- C:
["coding", "dancing", "baking"]
- D:
["coding", "running", "dancing", "baking"]
Answer
#### Answer: C
The addHobby
function receives two arguments, hobby
and hobbies
with the default value of the hobbies
array on the person
object.
First, we invoke the addHobby
function, and pass "running"
as the value for hobby
and an empty array as the value for hobbies
. Since we pass an empty array as the value for y
, "running"
gets added to this empty array.
Then, we invoke the addHobby
function, and pass "dancing"
as the value for hobby
. We didn't pass a value for hobbies
, so it gets the default value, the hobbies
property on the person
object. We push the hobby dancing
to the person.hobbies
array.
Last, we invoke the addHobby
function, and pass "baking"
as the value for hobby
, and the person.hobbies
array as the value for hobbies
. We push the hobby baking
to the person.hobbies
array.
After pushing dancing
and baking
, the value of person.hobbies
is ["coding", "dancing", "baking"]
142. What's the output?
class Bird {
constructor() {
console.log("I'm a bird. 🦢");
}
}
class Flamingo extends Bird {
constructor() {
console.log("I'm pink. 🌸");
super();
}
}
const pet = new Flamingo();
- A:
I'm pink. 🌸
- B:
I'm pink. 🌸
I'm a bird. 🦢
- C:
I'm a bird. 🦢
I'm pink. 🌸
- D: Nothing, we didn't call any method
Answer
#### Answer: B
We create the variable pet
which is an instance of the Flamingo
class. When we instantiate this instance, the constructor
on Flamingo
gets called. First, "I'm pink. 🌸"
gets logged, after which we call super()
. super()
calls the constructor of the parent class, Bird
. The constructor in Bird
gets called, and logs "I'm a bird. 🦢"
.
143. Which of the options result(s) in an error?
const emojis = ['🎄', '🎅🏼', '🎁', '⭐'];
/* 1 */ emojis.push('🦌');
/* 2 */ emojis.splice(0, 2);
/* 3 */ emojis = [...emojis, '🥂'];
/* 4 */ emojis.length = 0;
- A: 1
- B: 1 and 2
- C: 3 and 4
- D: 3
Answer
#### Answer: D
The const
keyword simply means we cannot redeclare the value of that variable, it's read-only. However, the value itself isn't immutable. The properties on the emojis
array can be modified, for example by pushing new values, splicing them, or setting the length of the array to 0.
144. What do we need to add to the person
object to get ["Lydia Hallie", 21]
as the output of [...person]
?
const person = {
name: "Lydia Hallie",
age: 21
}
[...person] // ["Lydia Hallie", 21]
- A: Nothing, object are iterable by default
- B:
*[Symbol.iterator]() { for (let x in this) yield* this[x] }
- C:
*[Symbol.iterator]() { yield* Object.values(this) }
- D:
*[Symbol.iterator]() { for (let x in this) yield this }
Answer
#### Answer: C
Objects aren't iterable by default. An iterable is an iterable if the iterator protocol is present. We can add this manually by adding the iterator symbol [Symbol.iterator]
, which has to return a generator object, for example by making it a generator function *[Symbol.iterator]() {}
. This generator function has to yield the Object.values
of the person
object if we want it to return the array ["Lydia Hallie", 21]
: yield* Object.values(this)
.
145. What's the output?
let count = 0;
const nums = [0, 1, 2, 3];
nums.forEach(num => {
if (num) count += 1
})
console.log(count)
- A: 1
- B: 2
- C: 3
- D: 4
Answer
#### Answer: C
The if
condition within the forEach
loop checks whether the value of num
is truthy or falsy. Since the first number in the nums
array is 0
, a falsy value, the if
statement's code block won't be executed. count
only gets incremented for the other 3 numbers in the nums
array, 1
, 2
and 3
. Since count
gets incremented by 1
3 times, the value of count
is 3
.
146. What's the output?
function getFruit(fruits) {
console.log(fruits?.[1]?.[1])
}
getFruit([['🍊', '🍌'], ['🍍']])
getFruit()
getFruit([['🍍'], ['🍊', '🍌']])
- A:
null
,undefined
, 🍌 - B:
[]
,null
, 🍌 - C:
[]
,[]
, 🍌 - D:
undefined
,undefined
, 🍌
Answer
#### Answer: D
The ?
allows us to optionally access deeper nested properties within objects. We're trying to log the item on index 1
within the subarray that's on index 1
of the fruits
array. If the subarray on index 1
in the fruits
array doesn't exist, it'll simply return undefined
. If the subarray on index 1
in the fruits
array exists, but this subarray doesn't have an item on its 1
index, it'll also return undefined
.
First, we're trying to log the second item in the ['🍍']
subarray of [['🍊', '🍌'], ['🍍']]
. This subarray only contains one item, which means there is no item on index 1
, and returns undefined
.
Then, we're invoking the getFruits
function without passing a value as an argument, which means that fruits
has a value of undefined
by default. Since we're conditionally chaining the item on index 1
offruits
, it returns undefined
since this item on index 1
does not exist.
Lastly, we're trying to log the second item in the ['🍊', '🍌']
subarray of ['🍍'], ['🍊', '🍌']
. The item on index 1
within this subarray is 🍌
, which gets logged.
147. What's the output?
class Calc {
constructor() {
this.count = 0
}
increase() {
this.count ++
}
}
const calc = new Calc()
new Calc().increase()
console.log(calc.count)
- A:
0
- B:
1
- C:
undefined
- D:
ReferenceError
Answer
#### Answer: A
We set the variable calc
equal to a new instance of the Calc
class. Then, we instantiate a new instance of Calc
, and invoke the increase
method on this instance. Since the count property is within the constructor of the Calc
class, the count property is not shared on the prototype of Calc
. This means that the value of count has not been updated for the instance calc points to, count is still 0
.
148. What's the output?
const user = {
email: "e@mail.com",
password: "12345"
}
const updateUser = ({ email, password }) => {
if (email) {
Object.assign(user, { email })
}
if (password) {
user.password = password
}
return user
}
const updatedUser = updateUser({ email: "new@email.com" })
console.log(updatedUser === user)
- A:
false
- B:
true
- C:
TypeError
- D:
ReferenceError
Answer
#### Answer: B
The updateUser
function updates the values of the email
and password
properties on user, if their values are passed to the function, after which the function returns the user
object. The returned value of the updateUser
function is the user
object, which means that the value of updatedUser is a reference to the same user
object that user
points to. updatedUser === user
equals true
.
149. What's the output?
const fruit = ['🍌', '🍊', '🍎']
fruit.slice(0, 1)
fruit.splice(0, 1)
fruit.unshift('🍇')
console.log(fruit)
- A:
['🍌', '🍊', '🍎']
- B:
['🍊', '🍎']
- C:
['🍇', '🍊', '🍎']
- D:
['🍇', '🍌', '🍊', '🍎']
Answer
#### Answer: C
First, we invoke the slice
method on the fruit array. The slice method does not modify the original array, but returns the value that it sliced off the array: the banana emoji.
Then, we invoke the splice
method on the fruit array. The splice method does modify the original array, which means that the fruit array now consists of ['🍊', '🍎']
.
At last, we invoke the unshift
method on the fruit
array, which modifies the original array by adding the provided value, ‘🍇’ in this case, as the first element in the array. The fruit array now consists of ['🍇', '🍊', '🍎']
.
150. What's the output?
const animals = {};
let dog = { emoji: '🐶' }
let cat = { emoji: '🐈' }
animals[dog] = { ...dog, name: "Mara" }
animals[cat] = { ...cat, name: "Sara" }
console.log(animals[dog])
- A:
{ emoji: "🐶", name: "Mara" }
- B:
{ emoji: "🐈", name: "Sara" }
- C:
undefined
- D:
ReferenceError
Answer
#### Answer: B
Object keys are converted to strings.
Since the value of dog
is an object, animals[dog]
actually means that we’re creating a new property called "object Object"
equal to the new object. animals["object Object"]
is now equal to { emoji: "🐶", name: "Mara"}
.
cat
is also an object, which means that animals[cat]
actually means that we’re overwriting the value of animals[``"``object Object``"``]
with the new cat properties.
Logging animals[dog]
, or actually animals["object Object"]
since converting the dog
object to a string results "object Object"
, returns the { emoji: "🐈", name: "Sara" }
.
151. What's the output?
const user = {
email: "my@email.com",
updateEmail: email => {
this.email = email
}
}
user.updateEmail("new@email.com")
console.log(user.email)
- A:
my@email.com
- B:
new@email.com
- C:
undefined
- D:
ReferenceError
Answer
#### Answer: A
The updateEmail
function is an arrow function, and is not bound to the user
object. This means that the this
keyword is not referring to the user
object, but refers to the global scope in this case. The value of email
within the user
object does not get updated. When logging the value of user.email
, the original value of my@email.com
gets returned.
152. What's the output?
const promise1 = Promise.resolve('First')
const promise2 = Promise.resolve('Second')
const promise3 = Promise.reject('Third')
const promise4 = Promise.resolve('Fourth')
const runPromises = async () => {
const res1 = await Promise.all([promise1, promise2])
const res2 = await Promise.all([promise3, promise4])
return [res1, res2]
}
runPromises()
.then(res => console.log(res))
.catch(err => console.log(err))
- A:
[['First', 'Second'], ['Fourth']]
- B:
[['First', 'Second'], ['Third', 'Fourth']]
- C:
[['First', 'Second']]
- D:
'Third'
Answer
#### Answer: D
The Promise.all
method runs the passed promises in parallel. If one promise fails, the Promise.all
method rejects with the value of the rejected promise. In this case, promise3
rejected with the value "Third"
. We’re catching the rejected value in the chained catch
method on the runPromises
invocation to catch any errors within the runPromises
function. Only "Third"
gets logged, since promise3
rejected with this value.
153. What should the value of method
be to log { name: "Lydia", age: 22 }
?
const keys = ["name", "age"]
const values = ["Lydia", 22]
const method = /* ?? */
Object[method](keys.map((_, i) => {
return [keys[i], values[i]]
})) // { name: "Lydia", age: 22 }
- A:
entries
- B:
values
- C:
fromEntries
- D:
forEach
Answer
#### Answer: C
The fromEntries
method turns a 2d array into an object. The first element in each subarray will be the key, and the second element in each subarray will be the value. In this case, we’re mapping over the keys
array, which returns an array which first element is the item on the key array on the current index, and the second element is the item of the values array on the current index.
This creates an array of subarrays containing the correct keys and values, which results in { name: "Lydia", age: 22 }
154. What's the output?
const createMember = ({ email, address = {}}) => {
const validEmail = /.+\@.+\..+/.test(email)
if (!validEmail) throw new Error("Valid email pls")
return {
email,
address: address ? address : null
}
}
const member = createMember({ email: "my@email.com" })
console.log(member)
- A:
{ email: "my@email.com", address: null }
- B:
{ email: "my@email.com" }
- C:
{ email: "my@email.com", address: {} }
- D:
{ email: "my@email.com", address: undefined }
Answer
#### Answer: C
The default value of address
is an empty object {}
. When we set the variable member
equal to the object returned by the createMember
function, we didn't pass a value for address, which means that the value of address is the default empty object {}
. An empty object is a truthy value, which means that the condition of the address ? address : null
conditional returns true
. The value of address is the empty object {}
.
155. What's the output?
let randomValue = { name: "Lydia" }
randomValue = 23
if (!typeof randomValue === "string") {
console.log("It's not a string!")
} else {
console.log("Yay it's a string!")
}
- A:
It's not a string!
- B:
Yay it's a string!
- C:
TypeError
- D:
undefined
Answer
#### Answer: B
The condition within the if
statement checks whether the value of !typeof randomValue
is equal to "string"
. The !
operator converts the value to a boolean value. If the value is truthy, the returned value will be false
, if the value is falsy, the returned value will be true
. In this case, the returned value of typeof randomValue
is the truthy value "number"
, meaning that the value of !typeof randomValue
is the boolean value false
.
!typeof randomValue === "string"
always returns false, since we're actually checking false === "string"
. Since the condition returned false
, the code block of the else
statement gets run, and Yay it's a string!
gets logged.
Orininally posted on - Alimammiya